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poker_menteur
5 Occurrences trouvées, Dernière modification :
re = tuple([nombre for nombre, valeur in comptage if nombre != 0]) #print signature, # décommente... re] # qualification correspondante de la main if main == "rien, petite ou grande suite": #... ce manquante permet de déterminer la main if lancer[0]==2: main = "grande suite" ... #print lancer, main(lancer) if lancers_possibles.has_key(lancer):
paradoxe_anniversaires
3 Occurrences trouvées, Dernière modification :
e birthday paradox is very famous in probability. If you take 23 people, there's about a 50/50 chance ... e birthday paradox is very famous in probability. If you take 23 people, there's about a 50/50 chance ... qrt(52) = 7.2, and it took 9 draws. Specifically, if you have a hash function with N possible outputs